(2x^2+30x+100)=(2916)

Solution for (2x^2+30x+100)=(2916) equation:

(2x^2+30x+100)=(2916)

We move all terms to the left:

(2x^2+30x+100)-((2916))=0

determiningTheFunctionDomain
(2x^2+30x+100)-2916=0

We get rid of parentheses

2x^2+30x+100-2916=0

We add all the numbers together, and all the variables

2x^2+30x-2816=0

a = 2; b = 30; c = -2816;
Δ = b2-4ac
Δ = 302-4·2·(-2816)
Δ = 23428
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{23428}=\sqrt{4*5857}=\sqrt{4}*\sqrt{5857}=2\sqrt{5857}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{5857}}{2*2}=\frac{-30-2\sqrt{5857}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{5857}}{2*2}=\frac{-30+2\sqrt{5857}}{4}
$